Grade 6 • Unit 10 HyperDoc

The Packing Plant: Volume, Nets & Surface Area

Welcome to the Bayview Snack Co. packing plant. Your shift has two jobs: figure out how much snack fits inside each box (volume) and how much cardboard it takes to build the box (surface area). Both come from the same flat piece of cardboard — a net. Bienvenido a la planta empacadora. Tu turno tiene dos trabajos: volumen y área total.

Standards: 6.G.A.2 & 6.G.A.4 Topic: Volume, Nets & Surface Area MCAP-aligned Work time: ~50 min

1 Engage

Hook & essential question

The plant just got a new cracker box. Before the machines start, you have to answer two questions about it: how many 1 cm unit cubes of cracker mix pack inside, and how much cardboard wraps the outside. Look at the box below.

length = 5 cm height = 4 cm width = 3 cm

New cracker box: 5 cm long, 3 cm wide, 4 cm tall.

Quick think (no calculator): Make a first guess for each. About how many cubes fit inside — closer to 20, 60, or 120? And which job needs more arithmetic, the inside or the outside? Jot your guesses in your notebook. You will check them in the Apply section.

Essential question: How can one flat net help me measure both the space inside a solid and the material around it?

2 Explore

Investigate before the lesson

Explore each tool below for a few minutes. As you go, hunt for one big idea: a 3D box and its flat net hold exactly the same faces — so the net is where surface area comes from.

Unfold experiment

Drag your eyes from the box on the left to the unfolded net on the right. The closed box has 6 rectangular faces; the net lays all 6 of them flat. Nothing is added or lost — you can fold the net right back into the box.

Closed box (3D)

top side front side bottom

Same box, unfolded into a net (6 faces)

Notice: Counting the cubes inside is volume. Adding up the area of all 6 flat faces is surface area. Same box — two different questions.

3 Explain

The math, in plain language

Volume counts the unit cubes that fill a solid; we measure it in cubic units (cm³, in³). Surface area counts the flat square units on the outside (cm², in²). Watch the little 3 and 2 — they tell you which question you are answering.

volume (V)
space inside, in cubic units · el volumen
base area (B)
area of one base face · el área de la base
net
a solid unfolded flat · la plantilla / red
surface area (SA)
all faces added up, in square units · el área total
prism
solid with two matching bases · el prisma
pyramid
one base, triangular sides meeting at a point · la pirámide

Volume of a prism

V = l × w × h

or V = B × h

Fill the bottom layer with cubes (that is the base area B), then stack the layers up the height.

Fractional edges

½ × ¾ × 2

Same formula — just multiply the fractions. Tiny cubes (like ¼-cm cubes) still pack the box; the formula counts them.

Surface area from a net

SA = sum of all face areas

Unfold the solid, find the area of each face, then add them. A box has 3 matching pairs of faces.

Pyramid surface area

SA = base + triangle faces

A pyramid's net is one base plus triangles. Find each area and add — the triangles use A = ½ × b × h.

Worked example A — volume of the cracker box

Back to the Engage box: l = 5 cm, w = 3 cm, h = 4 cm.

V = l × w × h = 5 × 3 × 4 = 15 × 4 = 60 cm³. So 60 unit cubes of cracker mix fit inside. (How close was your guess?)

Worked example B — fractional edges

A snack-sample box is ½ cm by ¾ cm by 2 cm.

V = ½ × ¾ × 2 = (½ × ¾) × 2 = ⅜ × 2 = ¾ cm³ (0.75 cm³). Multiply the fractions just like whole numbers.

Worked example C — surface area from the net

The cracker box (5 × 3 × 4) has 3 pairs of matching faces. Find one of each, double it, and add:

Face pair One face Two faces
front & back (5 × 4) 20 cm² 40 cm²
left & right (3 × 4) 12 cm² 24 cm²
top & bottom (5 × 3) 15 cm² 30 cm²

SA = 40 + 24 + 30 = 94 cm² of cardboard.

Level 1 · support Step-by-step helper / Ayuda paso a paso
  1. Ask first: inside or outside? Inside = volume (cubic units, ³). Outside = surface area (square units, ²).
  2. For volume, multiply all three numbers: l × w × h.
  3. For surface area, find the area of each face on the net, then add every face.
  4. Always end with the right unit: cm³ for volume, cm² for surface area. Volumen termina en unidades cúbicas (³); área total en unidades cuadradas (²).
Level 2 · enrichment Push your thinking

Two boxes have the same volume of 24 cm³ but different shapes: one is 2 × 3 × 4 and one is 1 × 2 × 12. Predict which one uses more cardboard (surface area), then check. Why does a long, thin box waste more material than a chunky one?

4 Apply

Show what you can do — auto-checked

1. The cracker box is 5 cm by 3 cm by 4 cm. What is its volume? (number only)

2. Using the net table, how many cm² of cardboard wrap that same 5 × 3 × 4 box? (Add all six faces.)

3. A sample box is ½ cm by ¾ cm by 2 cm. Which is its volume?

4. Which net folds into a closed rectangular box (a right rectangular prism)?

A B C

5. A square-pyramid candy topper has a 4 cm by 4 cm base and four triangular sides. Each triangle has base 4 cm and slant height 4.5 cm. Find the total surface area. SA = base + 4 triangles, where each triangle = ½ × 4 × 4.5.

base 4×4

6. A box has volume 48 cm³ and a base area of 8 cm². What is its height? (Use V = B × h.)

Level 1 · support Sentence starters for explaining

"This question asks about the ____ (inside / outside), so I used ____ units. I multiplied ____ × ____ × ____ (or added the faces ____ + ____ + ____). My answer is ____ cm³ or cm²."

"Esta pregunta es sobre el ____ (interior / exterior), así que usé unidades ____. Multipliqué ____ × ____ × ____ (o sumé las caras). Mi respuesta es ____ cm³ o cm²."

Level 2 · enrichment Reverse it

A prism has volume 90 cm³ and a height of 5 cm. Work backwards to find the base area B. Then name two different whole-number length × width rectangles that could be that base.

Teacher Notes & Answer Key (not printed)

Stage-by-Stage Notes (Engage → Explore → Explain → Apply → Reflect)

  • Engage: estimate how much cardboard wraps a box (surface area vs volume).
  • Explore: count unit cubes and unfold prisms into nets.
  • Explain: V = l·w·h; surface area = sum of all face areas from the net.
  • Apply: answer key below.
  • Reflect: students distinguish ft³ (volume) from ft²/cm² (surface area).

Apply — Answer Key

  • Q1 — Volume 5×3×4: 60 cm³.
  • Q2 — Surface area of that box: 2(15)+2(20)+2(12) = 30+40+24 = 94 cm².
  • Q3 — Fractional-edge volume (MC): answer c.
  • Q4 — Net of a closed box (MC): answer b.
  • Q5 — Pyramid surface area (4×4 base + 4 triangles): 52 cm².
  • Q6 — Height = V ÷ base area = 48 ÷ 8 (MC): answer c (6 cm).

Standard

CCSS 6.G.A.2 & A.4.

5 Reflect

Think about your thinking

A. Volume and surface area both describe the same box. In your own words, what is the difference, and how do the units (³ vs ²) help you keep them straight?

B. How does unfolding a solid into a net make surface area easier to find? Use the word "net" in your answer.

C. One thing that is now clear to me / Una cosa que ahora entiendo bien:

Your reflections save with this HyperDoc when you use Save as PDF or Save as DOC above.

6 Extend

Optional challenge project

Design a snack box for Bayview Snack Co.

On grid paper, design a new rectangular snack box and draw its net. Pick dimensions where at least one edge is a fraction or mixed number. Then:

  1. Label the length, width, and height on both the box and the net.
  2. Find the volume (how much snack fits inside).
  3. Find the surface area from your net.
  4. If cardboard costs $0.02 per cm², find the material cost for one box.

Diseña una caja de snack, dibuja su plantilla (net), y calcula el volumen, el área total y el costo del cartón.