6.DS.6d Group 1 · Extra Support

Practice Set · Part 1

Choose Appropriate Measures

Pick up where we left off

Name: Date: Group:

Where we left off

Our goal: With my small group, I can choose the best measure of center for a data set based on its shape — one step at a time, with support.

The big idea: An outlier pulls the mean toward it, so the median is the better measure of center when the data has an outlier.

Model to copy — Example 1 · Data with an outlier

  1. A top scorer's points in 7 games are 22, 24, 20, 25, 23, 21, 58. Which measure better shows a typical game: the mean or the median?
  2. Look for an outlier: 58
  3. Find the mean: 22 + 24 + 20 + 25 + 23 + 21 + 58 = 193; 193 ÷ 7 ≈ 27.6
  4. Put the values in order. Find the median: 20, 21, 22, 23, 24, 25, 58; 4th value → 23
  5. Compare each measure to the games: 27.6 > 25
  6. The median, 23, better shows a typical game.

Start here

You did these with your group. Now do them on your own — the model above is yours to copy.

  1. 1

    Same stepsFinish what the group started. Use the model above, step for step.

    Let's do one together: Choose the mean or the median for each data set. Set A: 4, 5, 6, 7, 8. Set B: 4, 5, 6, 7, 40. Does set A have an outlier? (No. The values are close together.) So which measure should we use for set A? (The mean. It uses every value, and no value pulls it.) Which value in set B is an outlier? (40) Does 40 pull the mean up or down? Which measure is better? (Up. The mean is 62 ÷ 5 = 12.4. The median, 6, is better.)

    My first step is ___ , because the problem asks for ___ .

    Show your work
  2. 2

    Warm restartThe mean of a data set is 20. A value is 26. What is the absolute deviation?

    1. A−6
    2. B6
    3. C26
    4. D46
  3. 3

    Warm restartThe mean of a data set is 15. One value is 11. What is the absolute deviation of that value from the mean?

    1. A−4
    2. B4
    3. C11
    4. D26
  4. 4

    Warm restartA data set has absolute deviations of 3, 1, 5, 2, 4. What is the MAD?

    1. A1
    2. B3
    3. C5
    4. D15
2.10 Small Group · Group 1 · Practice SetPart 1 of 4
6.DS.6d Group 1 · Extra Support

Practice Set · Part 2

Choose Appropriate Measures

Keep going

You answered these out loud. Now write them.

Answer, then say how you know — the reason is the part that counts.

  1. 5

    Think it throughWhat is the mean ticket price?

    1. A$50
    2. B$51
    3. C$85
    4. D$260

    Why is that the answer?

    I chose ___ because ___ .

  2. 6

    Think it throughWhat is the median ticket price?

    1. A$50
    2. B$51
    3. C$52
    4. D$85

    How do you know?

    I chose ___ because ___ .

  3. 7

    Think it throughWhich measure better describes a 'typical' ticket?

    1. AThe median, because the $260 outlier pulls the mean far above most prices
    2. BThe mean, because it uses every value
    3. CNeither — you should use the mode
    4. DThe mean, because $85 is between the extremes

    Explain your thinking.

    I chose ___ because ___ .

  4. 8

    Back to the modelWhat pattern do you notice about when median is the better choice?

    The median is better when the data has ___ because the mean gets pulled toward ___. The mean is better when the data is ___ because ___.

Sort it again — on paper this time

Write the letter of the group each one belongs in.

A — Use MeanB — Use Median
2.10 Small Group · Group 1 · Practice SetPart 2 of 4
6.DS.6d Group 1 · Extra Support

Practice Set · Part 3

Choose Appropriate Measures

Words and reasoning

Word bank · Banco de palabras

Mean (Media)Median (Mediana)Outlier (Valor atípico)Skewed (Sesgado)Data distribution (Distribución de datos)Variability (Variabilidad)Cluster (Grupo)

Use the words

Fill each blank with a word from the bank.

Explain the thinking

  1. 9

    Find the mistakeAnother student made this exact mistake in this lesson. Explain why it is wrong, then write what they should have done.

    The mistake: A common mistake in Appropriate Measures is defaulting to the mean just because "it uses all the data," without first checking whether an outlier or skewed shape is present.
  2. 10

    Say moreAs you sort scenarios into 'Use Mean' or 'Use Median,' what clue tells you a data set needs the median instead of the mean?

    I use the median when the data has ___.

  3. 11

    Change one numberGo back to Part 1 and pick one problem you already solved. Change one number in it, then solve your new version. Show every step.

    If ___ changed to ___ , then ___ .

    Show your work
2.10 Small Group · Group 1 · Practice SetPart 3 of 4
6.DS.6d Group 1 · Extra Support

Practice Set · Part 4

Choose Appropriate Measures

Show what you know

Last check

These two come from Lesson 2.9. If they are shaky, that is the lesson to revisit — not this one.

  1. 12

    Show what you knowQuick check — you've got this: Data set: 15, 18, 16, 17, 15, 72. Which measure of center best represents the data?

    1. AMean, because it uses all values
    2. BMean, because it is always best
    3. CMedian, because 72 is an outlier
    4. DNeither works for this data

    Explain your choice.

    I know it is ___ because ___ .

  2. 13

    From Lesson 2.9Quick check — you've got this: Data set: 4, 8, 6, 10, 2. The mean is 6. What is the MAD?

    1. A0
    2. B2.4
    3. C6
    4. D12
  3. 14

    From Lesson 2.9Which keeper should the coach start, and why?

    1. AKeeper B, because two shutouts is best
    2. BEither one, because the means are equal
    3. CKeeper A, because the smaller MAD (0.67) means more consistent performance
    4. DKeeper B, because a larger MAD means more skill

Be honest — this tells your teacher what to do next

I can…Not yetGetting thereGot it
I can choose the best measure of center for a data set based on its shape — one step at a time, with support.
I can explain why it works: An outlier pulls the mean toward it, so the median is the better measure of center when the data has an…
I can talk through each step out loud using a sentence frame and the lesson's key words.

One question I want to ask my group next time