7.6 Small Group · Group 2
Tier 1 Extension · Non-Routine Synthesis · Misconception Traps · Rigorous CER Proofs
Distance on the Coordinate Plane · Distance · Procedural Fluency · Real-World Applications
- You already can do this. So we go up a level, not up a number: find what is always true, show it a second way, and be ready to defend it with a reason instead of an answer.
- I will find the distance from (-3, 2) to (4, 2). Both have y = 2, so they sit on the same horizontal line.
- The points are on opposite sides of zero, so I add the absolute values.
- |-3| = 3 and |4| = 4.
- I add: 3 + 4 = 7. The distance between them is 7 units.
- Now let's find the distance from (2, 3) to (2, 8). What do these points share? The same x = 2, so it is a vertical line.
- These points are on the SAME side of zero (both positive), so do we add or subtract? We subtract.
- The distance is |8 - 3| = 5 units. When points sit on the same side of zero, subtract to find the distance.
- Now prove it: say why that move had to work at all — not just that it did.
- Sentence frame — convince a skeptic: "My method works because ___ . It would stop working if ___ ."
- Distance on the Coordinate Plane (Distancia en el plano de coordenadas) — The positive space between points, found from the absolute difference of coordinates on a horizontal or vertical line.
- Distance (Distancia) — How far apart two points are. It is never negative.
- Absolute value (Valor absoluto) — How far a number is from zero. It is never negative.
- Horizontal distance (Distancia horizontal) — How far apart two points are going left or right.
- Vertical distance (Distancia vertical) — How far apart two points are going up or down.
- Coordinate plane (Plano cartesiano) — A grid with a line going across and a line going up to plot points.
- A common mistake in Distance on the Coordinate Plane is subtracting the coordinates as if both points were on the same side of zero, instead of adding their absolute values when the points are on opposite sides. For example, to find the distance between (-6, 3) and (2, 3), a student might subtract 6 − 2 = 4, but since -6 and 2 are on opposite sides of zero, the absolute values must be added instead: |-6| + |2| = 6 + 2 = 8. The correct distance is 8 units, not 4. Before you submit, ask: 'Are these two points on opposite sides of zero — and if so, did I add the absolute values instead of subtracting?'
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1 FILL TABLE
Find the perimeter of each rectangle using its vertex coordinates.
Rectangle Vertices Width Height Perimeter Rect 1 Rect 2 ✏️ Scratchpad / Reasoning
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2 COORDINATE GRID
Plot these pairs and find each distance: A(-5, 3) to B(2, 3), and C(4, -2) to D(4, 4)
✏️ Workspace & Solution Steps
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3 MULTIPLE CHOICE
A rectangle has corners (1, 2), (1, 5), (5, 5), and (5, 2). What is its perimeter?
- A7 units
- B12 units
- C14 units
- D10 units
FormulaPut the numbers inWork it outAnswer with its unit -
4 MULTIPLE CHOICE
How far apart are the points (-2, 5) and (-2, -3)?
- A2 units
- B8 units
- C15 units
- D-8 units
✏️ Workspace & Solution Steps
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5 ERROR ANALYSIS
Find the Distance Error
- 1Problem:Find the distance between (-3, 4) and (5, 4)
- 2Student thinking:Subtract: 5 - 3 = 2
- 3Student answer:The distance is 2 units
Which step contains the error? Explain the mathematical misconception and write the correct calculation below.
✏️ Corrected Mathematical Work & Explanation -
6 OPEN RESPONSE
A rectangle has vertices at (-4, -2), (3, -2), (3, 5), and (-4, 5). Find the length, width, perimeter, and area of the rectangle. Show your work using absolute value.
✏️ Mathematical Justification & Response
Group Discussion Prompt: How does your visual model justify your mathematical solution?
Partner A: "I modeled this by identifying the relationship and..."
Partner B: "I agree with your step because the standard mathematical rule states..."
Complete each sentence stem to demonstrate precise mathematical reasoning:
Writing Task: Justify why your mathematical solution is accurate and complete.