Practice Set · Part 1
Apply Two-Variable Relationships to Solve Problems
Pick up where we left off
Where we left off
Our goal: With my small group, I can write an equation to represent the relationship between two variable quantities and use it to solve a real problem — one step at a time, with support.
The big idea: Write the relationship as an equation, substitute the known value, solve for the unknown, then interpret the solution in context.
Model to copy — Watch me test the car order
- The number of cars produced depends on the number of hours of operation. Every hour, the plant produces 2.5 cars.
- Let h = hours and c = cars. The equation is c = 2.5h. Check with the table: 8 hours gives 2.5 × 8 = 20 cars per shift.
- The order needs 1,000 cars, so substitute: 2.5h = 1,000.
- Divide both sides by 2.5: h = 1,000 ÷ 2.5 = 400 hours.
- Interpret it: 400 hours running 24 hours a day is about 17 days — about 2.5 weeks. That fits inside 3 weeks only if the plant runs 24 hours a day, 7 days a week.
Start here
You did these with your group. Now do them on your own — the model above is yours to copy.
- 1
Same stepsFinish what the group started. Use the model above, step for step.
Let's plan the car wash together: Last year the council washed 34 cars and raised $408. What did they charge per car? Divide: 408 ÷ 34 = $12. At $12 per car, let n = cars washed and t = total raised: t = 12n. The goal is $500, so 12n = 500 means n = 500 ÷ 12, which is about 41.7 — so they must wash at least 42 cars, because 41 cars raise only 41 × 12 = $492. Or fix the cars instead: if they predict 35 cars, then 35p = 500 gives p = 500 ÷ 35, about $14.29 — so they must charge at least $14.30 per car.My first step is ___ , because the problem asks for ___ .
Show your work - 2
Warm restartA table pairs x = 1, 2, 3 with y = 4, 8, 12. Which equation fits?
- Ay = 4x
- By = x + 3
- Cy = x + 4
- Dy = x ÷ 4
- 3
Warm restartA bike travels 12 miles every hour. Which equation gives distance d after h hours?
- Ad = 12h
- Bd = 12 + h
- Cd = h ÷ 12
- Dd = 12 − h
- 4
Warm restartIn the equation y = 5x, what is y when x = 6?
- A30
- B11
- C5
- D56
Practice Set · Part 2
Apply Two-Variable Relationships to Solve Problems
Keep going
You answered these out loud. Now write them.
Answer, then say how you know — the reason is the part that counts.
- 5
Think it throughBakery A charges $2 per cupcake plus a $10 delivery fee, so its cost equation is c = 2n + 10, where n is the number of cupcakes. Substituting Yelina's $110 budget, which equation should she solve to find n?
- A2n + 10 = 110
- B2n + 10 = 100
- C2n = 110 + 10
- Dn = 2(110) + 10
Why is that the answer?
I chose ___ because ___ .
- 6
Think it throughSolving 2n + 10 = 110 for Bakery A, how many cupcakes can Yelina buy?
- A50 cupcakes
- B55 cupcakes
- C60 cupcakes
- D45 cupcakes
How do you know?
I chose ___ because ___ .
- 7
Think it throughBakery B charges $2.50 per cupcake with no fee: cost = 2.5n. Solving 2.5n = 110 gives n = 44 cupcakes. Which bakery should Yelina choose to get more cupcakes within her $110 budget?
- ABakery A, because 50 cupcakes is more than 44 cupcakes
- BBakery B, because 2.5 is greater than 2
- CBakery A, because it has a delivery fee
- DThey are the same, because both cost exactly $110
Explain your thinking.
I chose ___ because ___ .
- 8
Back to the modelThe plant produces 2.5 cars per hour, and the order needs 1,000 cars. Solving 2.5h = 1,000 gives h = 400 hours. Why do you divide instead of multiply to find h?
I divide 1,000 by 2.5 because multiplication and division ___ each other.
Sort it again — on paper this time
Write the letter of the group each one belongs in.
- An 8-hour shift produces 20 cars
- Washing 34 cars raised $408 last year
- 24 hours of operation produce 60 cars
- Washing 42 cars raises $504
- Producing 1,000 cars takes 400 hours
- Washing 10 cars raises $120
- One hour of operation produces 2.5 cars
- The charge last year was $12 per car
Practice Set · Part 3
Apply Two-Variable Relationships to Solve Problems
Words and reasoning
Word bank · Banco de palabras
Use the words
Fill each blank with a word from the bank.
- A value of the variable that makes an equation true is a ___.
- To replace a variable with a number so you can compute is to ___.
- That amount or more — the smallest amount that still works — is ___ ___.
- To use what you already know to say what a future amount will be is to ___.
Explain the thinking
- 9
Find the mistakeAnother student made this exact mistake in this lesson. Explain why it is wrong, then write what they should have done.
The mistake: Adding the rate instead of multiplying — writing 2. 5 + 8 = 10. - 10
Say moreYou sorted facts between the assembly line (2.5 cars/hour) and the car wash ($12/car). How did you check that 'washing 42 cars raises $504' belonged with the car wash?
42 cars at $12 each is 42 × ___ = $___.
- 11
Change one numberGo back to Part 1 and pick one problem you already solved. Change one number in it, then solve your new version. Show every step.
If ___ changed to ___ , then ___ .
Show your work
Practice Set · Part 4
Apply Two-Variable Relationships to Solve Problems
Show what you know
Last check
These two come from Lesson 9.3. If they are shaky, that is the lesson to revisit — not this one.
- 12
Show what you knowQuick check — you've got this: The plant produces 2.5 cars per hour. Using 2.5h = 1,000, how many hours does the order of 1,000 cars take?
- A400 hours
- B2,500 hours
- C997.5 hours
- D40 hours
Explain your choice.
I know it is ___ because ___ .
- 13
From Lesson 9.3Quick check — you've got this: Recreation World charges $24.95 per month. Let m = number of months and c = total cost. Which equation represents the relationship?
- Ac = 24.95m
- Bc = 24.95 + m
- Cm = 24.95c
- Dc = m ÷ 24.95
- 14
From Lesson 9.3Once Diamond has both equations, how does she use them to decide which option is better?
- ASubstitute the same number of songs into both equations and compare the two total costs
- BAdd the two equations together to find one combined cost
- CPick whichever equation has the smaller numbers written in it, without solving anything
- DGraph only one equation and assume the other follows the same line
Be honest — this tells your teacher what to do next
| I can… | Not yet | Getting there | Got it |
|---|---|---|---|
| I can write an equation to represent the relationship between two variable quantities and use it to solve a real problem — one step at a time, with support. | |||
| I can explain why it works: Write the relationship as an equation, substitute the known value, solve for the unknown… | |||
| I can talk through each step out loud using a sentence frame and the lesson's key words. |
One question I want to ask my group next time