6.AT.11 Group 1 · Extra Support

Practice Set · Part 1

Apply Two-Variable Relationships to Solve Problems

Pick up where we left off

Name: Date: Group:

Where we left off

Our goal: With my small group, I can write an equation to represent the relationship between two variable quantities and use it to solve a real problem — one step at a time, with support.

The big idea: Write the relationship as an equation, substitute the known value, solve for the unknown, then interpret the solution in context.

Model to copy — Watch me test the car order

  1. The number of cars produced depends on the number of hours of operation. Every hour, the plant produces 2.5 cars.
  2. Let h = hours and c = cars. The equation is c = 2.5h. Check with the table: 8 hours gives 2.5 × 8 = 20 cars per shift.
  3. The order needs 1,000 cars, so substitute: 2.5h = 1,000.
  4. Divide both sides by 2.5: h = 1,000 ÷ 2.5 = 400 hours.
  5. Interpret it: 400 hours running 24 hours a day is about 17 days — about 2.5 weeks. That fits inside 3 weeks only if the plant runs 24 hours a day, 7 days a week.

Start here

You did these with your group. Now do them on your own — the model above is yours to copy.

  1. 1

    Same stepsFinish what the group started. Use the model above, step for step.

    Let's plan the car wash together: Last year the council washed 34 cars and raised $408. What did they charge per car? Divide: 408 ÷ 34 = $12. At $12 per car, let n = cars washed and t = total raised: t = 12n. The goal is $500, so 12n = 500 means n = 500 ÷ 12, which is about 41.7 — so they must wash at least 42 cars, because 41 cars raise only 41 × 12 = $492. Or fix the cars instead: if they predict 35 cars, then 35p = 500 gives p = 500 ÷ 35, about $14.29 — so they must charge at least $14.30 per car.

    My first step is ___ , because the problem asks for ___ .

    Show your work
  2. 2

    Warm restartA table pairs x = 1, 2, 3 with y = 4, 8, 12. Which equation fits?

    1. Ay = 4x
    2. By = x + 3
    3. Cy = x + 4
    4. Dy = x ÷ 4
  3. 3

    Warm restartA bike travels 12 miles every hour. Which equation gives distance d after h hours?

    1. Ad = 12h
    2. Bd = 12 + h
    3. Cd = h ÷ 12
    4. Dd = 12 − h
  4. 4

    Warm restartIn the equation y = 5x, what is y when x = 6?

    1. A30
    2. B11
    3. C5
    4. D56
9.4 Small Group · Group 1 · Practice SetPart 1 of 4
6.AT.11 Group 1 · Extra Support

Practice Set · Part 2

Apply Two-Variable Relationships to Solve Problems

Keep going

You answered these out loud. Now write them.

Answer, then say how you know — the reason is the part that counts.

  1. 5

    Think it throughBakery A charges $2 per cupcake plus a $10 delivery fee, so its cost equation is c = 2n + 10, where n is the number of cupcakes. Substituting Yelina's $110 budget, which equation should she solve to find n?

    1. A2n + 10 = 110
    2. B2n + 10 = 100
    3. C2n = 110 + 10
    4. Dn = 2(110) + 10

    Why is that the answer?

    I chose ___ because ___ .

  2. 6

    Think it throughSolving 2n + 10 = 110 for Bakery A, how many cupcakes can Yelina buy?

    1. A50 cupcakes
    2. B55 cupcakes
    3. C60 cupcakes
    4. D45 cupcakes

    How do you know?

    I chose ___ because ___ .

  3. 7

    Think it throughBakery B charges $2.50 per cupcake with no fee: cost = 2.5n. Solving 2.5n = 110 gives n = 44 cupcakes. Which bakery should Yelina choose to get more cupcakes within her $110 budget?

    1. ABakery A, because 50 cupcakes is more than 44 cupcakes
    2. BBakery B, because 2.5 is greater than 2
    3. CBakery A, because it has a delivery fee
    4. DThey are the same, because both cost exactly $110

    Explain your thinking.

    I chose ___ because ___ .

  4. 8

    Back to the modelThe plant produces 2.5 cars per hour, and the order needs 1,000 cars. Solving 2.5h = 1,000 gives h = 400 hours. Why do you divide instead of multiply to find h?

    I divide 1,000 by 2.5 because multiplication and division ___ each other.

Sort it again — on paper this time

Write the letter of the group each one belongs in.

A — Assembly line: 2.5 cars per hourB — Car wash: $12 per car
9.4 Small Group · Group 1 · Practice SetPart 2 of 4
6.AT.11 Group 1 · Extra Support

Practice Set · Part 3

Apply Two-Variable Relationships to Solve Problems

Words and reasoning

Word bank · Banco de palabras

solution (solución)substitute (sustituir)at least (al menos)predict (predecir)justify (justificar)

Use the words

Fill each blank with a word from the bank.

Explain the thinking

  1. 9

    Find the mistakeAnother student made this exact mistake in this lesson. Explain why it is wrong, then write what they should have done.

    The mistake: Adding the rate instead of multiplying — writing 2. 5 + 8 = 10.
  2. 10

    Say moreYou sorted facts between the assembly line (2.5 cars/hour) and the car wash ($12/car). How did you check that 'washing 42 cars raises $504' belonged with the car wash?

    42 cars at $12 each is 42 × ___ = $___.

  3. 11

    Change one numberGo back to Part 1 and pick one problem you already solved. Change one number in it, then solve your new version. Show every step.

    If ___ changed to ___ , then ___ .

    Show your work
9.4 Small Group · Group 1 · Practice SetPart 3 of 4
6.AT.11 Group 1 · Extra Support

Practice Set · Part 4

Apply Two-Variable Relationships to Solve Problems

Show what you know

Last check

These two come from Lesson 9.3. If they are shaky, that is the lesson to revisit — not this one.

  1. 12

    Show what you knowQuick check — you've got this: The plant produces 2.5 cars per hour. Using 2.5h = 1,000, how many hours does the order of 1,000 cars take?

    1. A400 hours
    2. B2,500 hours
    3. C997.5 hours
    4. D40 hours

    Explain your choice.

    I know it is ___ because ___ .

  2. 13

    From Lesson 9.3Quick check — you've got this: Recreation World charges $24.95 per month. Let m = number of months and c = total cost. Which equation represents the relationship?

    1. Ac = 24.95m
    2. Bc = 24.95 + m
    3. Cm = 24.95c
    4. Dc = m ÷ 24.95
  3. 14

    From Lesson 9.3Once Diamond has both equations, how does she use them to decide which option is better?

    1. ASubstitute the same number of songs into both equations and compare the two total costs
    2. BAdd the two equations together to find one combined cost
    3. CPick whichever equation has the smaller numbers written in it, without solving anything
    4. DGraph only one equation and assume the other follows the same line

Be honest — this tells your teacher what to do next

I can…Not yetGetting thereGot it
I can write an equation to represent the relationship between two variable quantities and use it to solve a real problem — one step at a time, with support.
I can explain why it works: Write the relationship as an equation, substitute the known value, solve for the unknown…
I can talk through each step out loud using a sentence frame and the lesson's key words.

One question I want to ask my group next time