6.AT.11 Group 2 · Challenge

Practice Set · Part 1

Apply Two-Variable Relationships to Solve Problems

Pick up where we left off

Name: Date: Group:

Where we left off

Our goal: I can write an equation to represent the relationship between two variable quantities and use it to solve a real problem, explain what each part stands for, and build one for a situation I have not seen before.

The big idea: Solving the equation is not the last step: decide what the answer means, and round up or down so it fits the situation.

Model to copy — Example · Money already raised

  1. The student council has already raised $140. They charge $12 to wash each car. Their goal is $500. How many more cars must they wash?
  2. Write an equation for the total raised: t = 12n + 140
  3. Substitute 500 for t: 12n + 140 = 500
  4. Subtract 140 from both sides: 12n = 500 − 140; 12n = 360
  5. Divide both sides by 12: n = 360 ÷ 12 = 30
  6. Check the answer: 12 × 30 + 140 = 500
  7. They must wash 30 more cars.

Start here

You did these with your group. Now do them on your own — the model above is yours to copy.

  1. 1

    Same stepsFinish what the group started. Use the model above, step for step.

    Try it together — then prove it: Last year the student council washed 34 cars and raised $408. This year the goal is $500. At the same price, how many cars must they wash? Divide both quantities by 34. What does 1 car raise? (408 ÷ 34 = 12, so $12 per car.) Scale $12 up to $500. Write an equation and solve it. (12n = 500, so n = 500 ÷ 12 ≈ 41.7) Why must they wash 42 cars, not 41? (41 × 12 = 492, which is less than $500. 41 cars are not enough, so round up to 42.) With 35 cars, what price per car reaches $500? (p = 500 ÷ 35 ≈ 14.29, so at least $14.29 per car.)
    Show your work
  2. 2

    Warm restartA table pairs x = 1, 2, 3 with y = 4, 8, 12. Which equation fits?

    1. Ay = x + 3
    2. By = 4x
    3. Cy = x + 4
    4. Dy = x ÷ 4

    How do you know?

  3. 3

    Warm restartA bike travels 12 miles every hour. Which equation gives distance d after h hours?

    1. Ad = 12h
    2. Bd = 12 + h
    3. Cd = h ÷ 12
    4. Dd = 12 − h

    How do you know?

  4. 4

    Warm restartIn the equation y = 5x, what is y when x = 6?

    1. A5
    2. B11
    3. C30
    4. D56

    How do you know?

9.4 Small Group · Group 2 · Practice SetPart 1 of 4
6.AT.11 Group 2 · Challenge

Practice Set · Part 2

Apply Two-Variable Relationships to Solve Problems

Keep going

You answered these out loud. Now write them.

Answer, then say how you know — the reason is the part that counts.

  1. 5

    Think it throughBakery A charges $2 per cupcake plus a $10 delivery fee, so its cost equation is c = 2n + 10, where n is the number of cupcakes. Substituting Yelina's $110 budget, which equation should she solve to find n?

    1. A2n + 10 = 110
    2. B2n + 10 = 100
    3. C2n = 110 + 10
    4. Dn = 2(110) + 10

    Why is that the answer?

  2. 6

    Think it throughSolving 2n + 10 = 110 for Bakery A, how many cupcakes can Yelina buy?

    1. A45 cupcakes
    2. B50 cupcakes
    3. C55 cupcakes
    4. D60 cupcakes

    How do you know? Give a second reason as well.

  3. 7

    Think it throughBakery B charges $2.50 per cupcake with no fee: cost = 2.5n. Solving 2.5n = 110 gives n = 44 cupcakes. Which bakery should Yelina choose to get more cupcakes within her $110 budget?

    1. ABakery A, because 50 cupcakes is more than 44 cupcakes
    2. BBakery B, because 2.5 is greater than 2
    3. CBakery A, because it has a delivery fee
    4. DThey are the same, because both cost exactly $110

    Explain your thinking. What would have to change for a different choice to be right?

  4. 8

    Back to the modelThe plant produces 2.5 cars per hour, and the order needs 1,000 cars. Solving 2.5h = 1,000 gives h = 400 hours. Why do you divide instead of multiply to find h?

Sort it again — on paper this time

Write the letter of the group each one belongs in.

A — Assembly line: 2.5 cars per hourB — Car wash: $12 per car
9.4 Small Group · Group 2 · Practice SetPart 2 of 4
6.AT.11 Group 2 · Challenge

Practice Set · Part 3

Apply Two-Variable Relationships to Solve Problems

Words and reasoning

Word bank · Banco de palabras

solution (solución)substitute (sustituir)at least (al menos)predict (predecir)justify (justificar)Equation (Ecuación)Inverse operation (Operación inversa)Work backward (Trabajar hacia atrás)

Use the words

Fill each blank with a word from the bank.

Explain the thinking

  1. 9

    Find the mistakeAnother student made this exact mistake in this lesson. Explain why it is wrong, then write what they should have done.

    The mistake: Adding the rate instead of multiplying — writing 2. 5 + 8 = 10.
  2. 10

    Say moreYou sorted facts between the assembly line (2.5 cars/hour) and the car wash ($12/car). How did you check that 'washing 42 cars raises $504' belonged with the car wash?

  3. 11

    Write your ownWrite your own problem about this situation, then solve it and show the answer. The situation: An assembly line at an automobile manufacturing plant runs in 8-hour shifts and produces 2.5 cars per hour. Next to it, an order form reads: 1,000 cars needed in 3 weeks. A table shows: 1 hour, 2.5 cars. 8 hours, 20 cars. 16 hours, 40 cars. 24 hours, 60 cars.

    Show your work
9.4 Small Group · Group 2 · Practice SetPart 3 of 4
6.AT.11 Group 2 · Challenge

Practice Set · Part 4

Apply Two-Variable Relationships to Solve Problems

Show what you know

Last check

These two come from Lesson 9.3. If they are shaky, that is the lesson to revisit — not this one.

  1. 12

    Show what you knowExplain your thinking — The plant produces 2.5 cars per hour. Using 2.5h = 1,000, how many hours does the order of 1,000 cars take?

    1. A40 hours
    2. B400 hours
    3. C997.5 hours
    4. D2,500 hours

    Explain your choice.

  2. 13

    From Lesson 9.3Explain your thinking — Recreation World charges $24.95 per month. Let m = number of months and c = total cost. Which equation represents the relationship?

    1. Ac = 24.95m
    2. Bc = 24.95 + m
    3. Cm = 24.95c
    4. Dc = m ÷ 24.95

    How do you know?

  3. 14

    From Lesson 9.3Once Diamond has both equations, how does she use them to decide which option is better?

    1. AAdd the two equations together to find one combined cost
    2. BPick whichever equation has the smaller numbers written in it, without solving anything
    3. CSubstitute the same number of songs into both equations and compare the two total costs
    4. DGraph only one equation and assume the other follows the same line

    How do you know?

Be honest — this tells your teacher what to do next

I can…Not yetGetting thereGot it
I can write an equation to represent the relationship between two variable quantities and use it to solve a real problem, explain what each part stands for, and build one for a situation I have not seen before.
I can explain why it works: Solving the equation is not the last step: decide what the answer means…
I can justify my answer to a skeptic and connect it to a second strategy or representation.

One question I want to ask my group next time